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GCSE Chemistry Revision
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GCSE Chemistry revision
Properties of hydrocarbons
Carbon compounds as fuels and feedstock
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AQA student objectives
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Revision summary
Key knowledge
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What Are Alkanes?
- Alkanes are a homologous series of hydrocarbons containing only carbon and hydrogen atoms with no double bonds.
- The first four alkanes are methane (CH₄), ethane (C₂H₆), propane (C₃H₈), and butane (C₄H₁₀).
Boiling Point and Physical State
- The boiling point of alkanes increases as the length of the carbon chain increases.
- Shorter alkanes (1–4 carbon atoms) have low boiling points and exist as gases at room temperature.
- Longer alkanes (more than 4 carbons) are liquids at room temperature, and very long-chain alkanes can be solids.
Volatility and Viscosity
- Shorter alkanes are more volatile, meaning they evaporate more easily due to their low boiling points.
- Longer alkanes are more viscous, meaning they are thick and sticky, similar to honey.
Flammability
- Shorter alkanes are more flammable, meaning they ignite and burn more easily than longerchain alkanes.
- This makes short-chain alkanes particularly useful as fuels, as they release large amounts of energy when burned.
Complete Combustion of Alkanes
- Complete combustion occurs when a hydrocarbon reacts with sufficient oxygen to produce carbon dioxide and water, releasing energy.
- Complete combustion is an exothermic reaction, meaning energy is released to the surroundings.
- During combustion, the carbon and hydrogen in the hydrocarbon are oxidised, forming CO₂ and H₂O respectively.
Balancing Combustion Equations
- To balance a combustion equation, first write the unbalanced equation with the alkane reacting with O₂ to form CO₂ and H₂O.
- Balance carbon atoms first by adjusting the number of CO₂ molecules on the right-hand side.
- Balance hydrogen atoms next by adjusting the number of H₂O molecules, remembering each H₂O contains two hydrogen atoms.
- Finally, balance oxygen atoms by adjusting the number of O₂ molecules on the left-hand side.
Worked Example: Combustion of Propane
- The balanced equation for the complete combustion of propane is C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
- Three CO₂ molecules are needed to account for the three carbon atoms, and four H₂O molecules account for the eight hydrogen atoms.
- The five O₂ molecules on the left provide the 10 oxygen atoms needed to balance the right-hand side (6 from CO₂ + 4 from H₂O).
Worked Example: Combustion of Nonane
- The balanced equation for the complete combustion of nonane is C₉H₂₀ + 14O₂ → 9CO₂ + 10H₂O.
- Nine CO₂ molecules balance the nine carbon atoms, and ten H₂O molecules balance the twenty hydrogen atoms in nonane.
- There are 28 oxygen atoms on the right-hand side (18 from CO₂ + 10 from H₂O), requiring 14 O₂ molecules on the left.